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Physics Group 4 Project Essay, Research Paper
Physics Group 4
Project ??????????? After being
set our initial topic of the bath tub, we chose as a group to investigate the
heat lost from a bath tub.? We initially
experimented with ideas such as using different shapes, sizes and materials.? Eventually, we decided that the easiest
option was to investigate how the thickness of a bath tub effects the heat
loss, as well as how conduction, convection (evaporation) and radiation
effected the heat lost from a bath tub and how we could reduce these forms of
heat loss. We chose to use vacuum formed plastic bath tubs as they were the
quickest to build, and we did not want to waste valuble experimenting time
building lots of bath tubs.? The
polyethene plastic also mimicked the material of a real bath tub fairly
successfully.The investigation of energy (heat) lost in different bath
tubs. ??????????? We began
our investigation by determining the specific heat capacity of water. In order
to do this, we took a known mass of water in an insulated beaker and gave it a
known quantity of energy by using an emersion heater.? We also used an accurate thermometer in order to take the
temperature change in the water.? We
then used the equation: ??????????? E = mc∆t We then rearranged the formula to give: ??????????? c = E/m∆t In order to calculate the specific heat capacity of water
(c), we took the known quantities of mass, energy and the change in temperature
and inserted them into the above equation. In order to calculate the energy
given to the water, we used electricity to heat the water, by doing this we
were able to calculate the energy using P = VI.? We measured both the voltage and the current that we used to heat
the water.? We had previously weighed
the water and hence we knew the mass, and the change in temperature we measured
using a thermometer.? Hence we were able
to calculate the following values for the specific heat capacity of water: Test 1 Test 2 Test 3 Average Specific heat capacity of water 4745 4723 4216 4561 ??????????? The actual
specific heat capacity of water is 4200.?
We would expect our results to be lower than this value.? However, the beaker was very well insulated
with a lid and hence little heat would have been lost to the surroundings.? The high values can be explained due to: –
The inaccuracy of the probe thermometer we used.? We later found it was not the most accurate
thermometer available to us.? For the
remainder of our experiments we used a far better digital probe type
thermometer. –
The inaccuracy of the digital ammeters, voltmeters and the
unreliability of the power pack and the immersion heater. –
The impurities in the water which was not deionised.Background to our experiment ??????????? We
researched the different methods of heat loss and came up with the following
information: Conduction: The mechanism by which heat energy is
transferred through solid materials. In the case of our experiment, the heat
from the water will be transferred to a certain extent through the plastic
walls of the bath tub by conduction. Evaporation: The mechanism by which most energetic molecules
escape from the water surface leaving the less energetic molecules behind.? This means the internal energy of the water
is then lowered and its temperature is decreased. Convection: The mechanism by which fluid ?currents?, caused
by the differential densities of hot and cold fluids, move.? As the fluid gets ?hot? the particles
vibrate more, and therefore expand, become less dense and rise.? These particles then cool, become less dense
and sink. For the purpose of this experiment, I will consider the heat
lost by evaporation and conduction as one and the same thing as they are nearly
impossible to separate in a liquid such as water. Radiation: The mechanism by which energy from the water is
lost to the surroundings by electromagnetic waves.? This occurs even at low temperatures.? The Investigation ??????????? We began
our experiment by building two vacuum formed bath tubs of different
thicknesses.? We decided that in order
to investigate the effect of thickness as well as the heat loss from
conduction, convection and radiation we would undertake the following
experiments. 1)
We would fill both bath tubs with 700g of water and heat them
up to approximately 42.5 degrees, the temperature of an average bath tub.? We would then measure the heat lost from
both the thick and thin bath tubs in a 45 minute period.? We will record the change in temperature
every five minutes and from this hopefully plot a heat loss curve. 2)
We will then put a lid on the bath tubs to reduce the heat
loss due to evaporation and repeat the same experiment. 3)
We will then put insulation around the bath tubs to reduce the
heat loss due to conduction and repeat the same experiment. 4)
We will the paint the bath tubs silver to reduce the heat loss
due to radiation and repeat the same experiment. From these experiments we hope to
be able to calculate the heat loss due to conduction, convection and radiation
by virtually eliminating each of these forms of heat loss in turn and thereby
calculating? how much is lost through
each of these forms of heat loss. ????? We
wanted to make our measurements of heat loss as accurate as possible.? After our initial experience with the
inaccuracy of the
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